3(1[2y+5]1)=33

Solution for 3(1[2y+5]1)=33 equation:

Simplifying
3(1[2y + 5] * 1) = 33

Reorder the terms:
3(1[5 + 2y] * 1) = 33

Reorder the terms for easier multiplication:
3(1 * 1[5 + 2y]) = 33

Multiply 1 * 1
3(1[5 + 2y]) = 33
3([5 * 1 + 2y * 1]) = 33
3([5 + 2y]) = 33
(5 * 3 + 2y * 3) = 33
(15 + 6y) = 33

Solving
15 + 6y = 33

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-15' to each side of the equation.
15 + -15 + 6y = 33 + -15

Combine like terms: 15 + -15 = 0
0 + 6y = 33 + -15
6y = 33 + -15

Combine like terms: 33 + -15 = 18
6y = 18

Divide each side by '6'.
y = 3

Simplifying
y = 3